Section II

Questions 1 - 6

Question 1
E
P and R must be carriers of the recessive allele, because they have both had children with the disease, and these children must have inherited a recessive allele from each parent.

Similarly, both of Q’s parents must be heterozygous. Since Q does not have the disease, she has a 1/3 chance of being homozygous normal, and a 2/3 chance of being heterozygous.

Question 2
x = 9/2 or 4.5 ; y = 6 ; z =3

There are 6 carbons in glucose and so 6 CO₂ must be formed. In addition 6 H’s forms 3 H₂O. Finally balance the oxygen on each side.

Question 3
A

The area of the face is πr² = 0.01π
Pressure = 250 / 0.01π = 25,000 / π Pa

Question 4
1 = C
2 = D
3 = A
4 = E
5 = B
6 = F
7 = E

Question 5
A

Simply multiply 9 x 10^-23 by 3 x 10⁶ = 2.7 x 10^-16
Now divide by 1 x10³ to convert to kg.

Question 6
D

At this point on the graph, the volume of the lungs is decreasing (expiration), so the muscles are relaxing, allowing the lungs to deflate.

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